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  • A heavy particle of mass 0.50 kg is hanging from a string fixed with the roof. Find the force exerted (in Newton)  by the string on the particle. Take g = 9.8 m/s2 <img sr

A heavy particle of mass 0.50 kg is hanging from a string fixed with the roof. Find the force exerted (in Newton)  by the string on the particle. Take g = 9.8 m/s2

Option: 1

4.9
 


Option: 2

7.2


Option: 3

5.6


Option: 4

9.5


Answers (1)

 

 

As we learned 

  1. Gravitational force (Weight):-

  • Definition- Force with which earth attracts an object.

  • It is denoted by W=mg, where m=mass of the body and g= acceleration due to gravity.                                                   

2.    Tension(T):-

  • Force exerted by taut string, rope or chain against pulling force.

  • Tension remains the same as long as the string is the same only in case of a massless string.

So  The forces acting on the particle are-

  1.  pull of the earth, 0.50\; kg \times 9.8\; m/s^{2} = 4.9 N, vertically downward
  2. pull of the string, T vertically upward.

The particle is at rest with respect to the earth (which we assume to be an inertial frame). Hence, the sum of the forces should be zero. Therefore, T is 4.9 N acting vertically upward.

Posted by

Kshitij

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