Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A hollow cylindrical conductor has length of 3.14 m, while its inner and outer diameters are 4 mm and 8 mm respectively. The resistance of the conductor is <img alt="n\times 10^{-3}\Omega" src

A hollow cylindrical conductor has length of 3.14 m, while its inner and outer diameters are 4 mm and 8 mm respectively. The resistance of the conductor is n\times 10^{-3}\Omega..If the resistivity of the material is 2.4\times 10^{8}\Omega m . The value of n is

Option: 1

2


Option: 2

__


Option: 3

__


Option: 4

__


Answers (1)

best_answer

\begin{aligned} & \mathrm{R}=\frac{\rho \ell}{\mathrm{A}} \Rightarrow \mathrm{R}=\frac{\rho \ell}{\pi\left(\mathrm{r}_2^2-\mathrm{r}_1^2\right)} \\ & \mathrm{R}=\frac{2.4 \times 10^{-8} \times 3.14}{\pi\left(4^2-2^2\right) \times 10^{-6}} \\ & \mathrm{R}=2 \times 10^{-3} \Omega \end{aligned}

Posted by

himanshu.meshram

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech ECE cut-offs for female candidates go up at top NITs
anam-khan

JEE Main 2025 Session 2 City Slip (OUT) Live: Admit card likely on March 29 at jeemain.nta.nic.in; cut-offs
anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads

Latest Question