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  • A junction diode is connected to a 10 V source and  resistor as shown in figure. The slope

A junction diode is connected to a 10 V source and 10^{3}\Omega resistor as shown in figure. The slope of load line on the characteristic curve of diode will be:

Option: 1

10^{-2} \mathrm{AV}^{-1}


Option: 2

10^{-3} \mathrm{AV}^{-1}


Option: 3

10^{-4} \mathrm{AV}^{-1}


Option: 4

10^{-5} \mathrm{AV}^{-1}


Answers (1)

best_answer

If V is the voltage across the junction and I is the circuit current, then

\mathrm{\mathrm{V}+\mathrm{IR}=\mathrm{E} \quad \text { or } \quad \mathrm{I}=\frac{\mathrm{E}}{\mathrm{R}}-\frac{\mathrm{V}}{\mathrm{R}}=-\frac{\mathrm{V}}{\mathrm{R}}+\frac{\mathrm{E}}{\mathrm{R}}}

\mathrm{\text { Slope of load line }=-\frac{1}{\mathrm{R}}=\frac{1}{1000}=10^{-3} \mathrm{AV}^{-1}}

Posted by

Gaurav

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