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- A laboratory experiment involves measuring the thickness of a thin glass sheet using a screw gauge. The main scale reading is 2.5 mm, and the circular scale is divided into 50 divisions. The screw
A laboratory experiment involves measuring the thickness of a thin glass sheet using a screw gauge. The main scale reading is 2.5 mm, and the circular scale is divided into 50 divisions. The screw gauge has a pitch of 0.5 mm, and there is a positive zero error of 0.04 mm.
Calculate the actual thickness of the glass sheet.
160mm
27.46mm
200 mm
20 mm
Answers (1)
Given: Main scale reading = 2.5 mm
Number of circular scale divisions = 50
Pitch of screw gauge (p) = 0.5 mm
Positive zero error (Z.E.) = 0.04 mm
The actual reading on the circular scale (C.S.R.) is given by:
Plugging in the values:
The corrected reading is the difference between the circular scale reading and the zero error:
Corrected reading = C.S.R. − Z.E.
Plugging in the values:
Corrected reading = 25 mm − 0.04 mm = 24.96 mm
The total reading is the sum of the main scale reading and the corrected reading:
Total reading = Main scale reading + Corrected reading Plugging in the values:
Total reading = 2.5 mm + 24.96 mm = 27.46 mm
Therefore, the actual thickness of the glass sheet is 27.46 mm.
Therefore, the correct option is 2.
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