Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A laboratory experiment involves measuring the thickness of a thin glass sheet using a screw gauge. The main scale reading is 2.5 mm, and the circular scale is divided into 50 divisions. The screw

A laboratory experiment involves measuring the thickness of a thin glass sheet using a screw gauge. The main scale reading is 2.5 mm, and the circular scale is divided into 50 divisions. The screw gauge has a pitch of 0.5 mm, and there is a positive zero error of 0.04 mm.

Calculate the actual thickness of the glass sheet.

Option: 1

160mm


Option: 2

27.46mm


Option: 3

200 mm


Option: 4

20 mm


Answers (1)

best_answer

Given: Main scale reading = 2.5 mm

Number of circular scale divisions = 50

Pitch of screw gauge (p) = 0.5 mm

Positive zero error (Z.E.) = 0.04 mm

The actual reading on the circular scale (C.S.R.) is given by:

\text { C.S.R. }=\frac{\text { Number of circular scale divisions }}{\text { Number of main scale divisions }} \times \text { Pitch }

Plugging in the values:

\text { C.S.R. }=\frac{10}{1} \times 0.5 \mathrm{~mm}=5 \mathrm{~mm}

The corrected reading is the difference between the circular scale reading and the zero error:

Corrected reading = C.S.R. − Z.E.

Plugging in the values:

Corrected reading = 25 mm − 0.04 mm = 24.96 mm

The total reading is the sum of the main scale reading and the corrected reading:

Total reading = Main scale reading + Corrected reading Plugging in the values:

Total reading = 2.5 mm + 24.96 mm = 27.46 mm

Therefore, the actual thickness of the glass sheet is 27.46 mm.

Therefore, the correct option is 2.

 

Posted by

Anam Khan

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA Exam Changes Live: Reforms in NEET UG, JEE Main, CUET; test centres, question papers, biometric data
anam-khan

NTA to not hold recruitment exams; will be restructured in 2025: Dharmendra Pradhan
anam-khan

JEE Main 2025: BTech ECE remains among top engineering choices; NIT cut-offs

Latest Question