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A large cylinder of helium filled at 2000 \mathrm{~mm}  of \mathrm{Hg} had a small orifice through which helium escaped into evacuated space at the rate of 6.4 moles/ hour. How long would it take for 10 mole of CO were confined of the same pressure -

Option: 1

 2.1 hour
 


Option: 2

 4.2 hour
 


Option: 3

5.6 hour
 


Option: 4

 11.2 hour

 


Answers (1)

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\begin{aligned} \mathrm{\frac{r_{\text {He }}}{r_{C O}} }&\mathrm{ =\sqrt{\frac{M_{C O}}{M_{\text {He }}}}=\sqrt{\frac{21}{4}}=2.65 }\\ &\mathrm{ \Rightarrow r_{C O}=\frac{r_{\text {He }}}{2.65}=\frac{6.4}{2.65}=2.4 \text { moles } / \text { hours } }\\ &\mathrm{ \Rightarrow t=\frac{10}{2.4} \approx 4.2 \text { hours }}\\ \end{aligned}
It would take 4.2 hour for 10 mole of co to leak through a similar orifice of the co were confined of the same pressure.

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Anam Khan

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