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  • A light beam travelling in the -direction is described by the electric field: <img alt="\mathrm{E_y=27

A light beam travelling in the \mathrm{x}-direction is described by the electric field: \mathrm{E_y=270 \sin \omega(t-x / c)}. An electron is constrained to move along the \mathrm{y}-direction with speed of \mathrm{2 \times 10^7 \mathrm{~m} / \mathrm{s}}. The maximum electric force on the electron is
 

Option: 1

4.32 \times 10^{-17} \mathrm{~N}

 


Option: 2

5.32 \times 10^{-17} \mathrm{~N}
 


Option: 3

4.62 \times 10^{-17} \mathrm{~N}
 


Option: 4

3.12 \times 10^{-17} \mathrm{~N}


Answers (1)

best_answer

\mathrm{ E=E_0 \sin \omega(t-x / c) }

\mathrm{ E_0=270 \mathrm{~V} / \mathrm{m} }

\mathrm{ B_0=\frac{E_0}{\mathrm{c}}=9 \times 10^{-7} \mathrm{~T} }

\mathrm{ F_e=q E_0=1.6 \times 10^{-19} \times 270=4.32 \times 10^{-17} \mathrm{~N}}

Hence option 1 is correct.



 

Posted by

vinayak

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