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A logic gate having two inputs A and B and output C has the following truth table.

                A                      B                  C
   1             1                0
   1             0                1
   0             1                   1
   0             0                1

It is

Option: 1

An OR gate


Option: 2

An AND gate


Option: 3

A NOR gate


Option: 4

A NAND gate


Answers (1)

best_answer

The given truth table follows a NAND gate whose output is 1 only if at least one of its input is zero. Its Boolean expression is
\mathrm{Y=\overline{A \cdot B} }
So that \mathrm{\overline{1 \cdot 1}=\overline{1}=0 }
\mathrm{\begin{aligned} & \overline{1 \cdot 0}=\overline{0}=1 \\ & \overline{0 \cdot 1}=\overline{0}=1 \\ & \overline{0 \cdot 0}=\overline{0}=1 \end{aligned} }
 

Posted by

himanshu.meshram

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