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  • A long solenoid carrying a current produces a magnetic field B along it's axis. If the current is doubled and the number of turns per cm is halved, the new value of magnetic field will be equal

A long solenoid carrying a current produces a magnetic field B along it's axis. If the current is doubled and the number of turns per cm is halved, the new value of magnetic field will be equal to

Option: 1

\mathrm {B}


Option: 2

\mathrm {2B}


Option: 3

\mathrm {4B}


Option: 4

\mathrm {\frac{B}{2}}


Answers (1)

best_answer

Magnetic field at the axis of soleoid \mathrm{= B=\mu_{0}ni}

Initial :  \mathrm{B_{1}= \mu_{0}n_{1}i_{1}= B}

Final :  \mathrm{B_{2}= \mu_{0}n_{2}i_{2}}

            \mathrm{n_{2}=\frac{n_{1}}{2}, i_{2}=2 i_{1} }\\

            \mathrm{\therefore B_{1}=B_{2}=B}

Hence the correct answer is option 1.

Posted by

Rishi

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