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A long solenoid is fabricated by closely winding a wire of diameter 0.5 mm over a cylindrical nonmagnetic frame so that the successive turns nearly touch each other. What would be the magnetic field B at the centre of the solenoid if it carries a current of 2.5 A ?

Option: 1

\pi \times 10^{-3} \mathrm{~T}


Option: 2

2 \pi \times 10^{-3} \mathrm{~T}


Option: 3

4 \pi \times 10^{-3} \mathrm{~T}


Option: 4

None of these


Answers (1)

best_answer

\mathrm{n}=\frac{1}{\mathrm{~d}}=\frac{2}{1 \times 10^{-3}} / \mathrm{m} \\

\mathrm{ \mathrm{B}=\mu_0 \mathrm{ni} \\ } \\

\mathrm{ =4 \pi \times 10^{-7} \times \frac{2}{10^{-3}} \times 2.5=2 \pi \times 10^{-3} \mathrm{~T} } \\

Posted by

Ritika Harsh

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