Get Answers to all your Questions

header-bg qa

A loss –free transformer having 100 turns in primary is used to transmit 10 kW of power. The input voltage is 200 V and power is transmitted at 5 kV. The currents in the primary and secondary of the transformer are:

Option: 1

2 A and 50 A


Option: 2

50 A and 2 A


Option: 3

25 A and 4 A


Option: 4

12.5 A and 8 A


Answers (1)

best_answer

\mathrm{\begin{aligned} & \mathrm{N}_P=100, \mathrm{P}_{\mathrm{i}}=10 \mathrm{~kW}, \mathrm{~V}_{\mathrm{i}}=200 \mathrm{~V} \\ & \therefore \quad \mathrm{I}_{\mathrm{P}}=\frac{\mathrm{P}_{\mathrm{i}}}{\mathrm{V}_{\mathrm{i}}}=\frac{10000}{200}=50 \mathrm{~A} \\ & \text { Input power }=\text { Output power (Neglecting all losses) } \\ & \therefore \quad \mathrm{I}_{\mathrm{S}}=\frac{\mathrm{P}_{\mathrm{i}}}{\mathrm{V}_{\mathrm{o}}}=\frac{10000}{5000}=2 \mathrm{~A} \end{aligned} }

Posted by

jitender.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE