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  • A man is rest against the inner wall of a rotor which is moving with angular velocity . If the radius of the r

A man is rest against the inner wall of a rotor which is moving with angular velocity \omega. If the radius of the rotor is 2m and the coefficient of static friction between wall and the person is 0.2 . Find minimum angular velocity (in rad/sec)  for man to be at rest. (g= 10m/s2)

Option: 1

5


Option: 2

8


Option: 3

10


Option: 4

15


Answers (1)

best_answer

As we learned

Sticking of Person with the wall of Rotor(Death well) -

F = weight of person (mg)

\mu R=mg

\mu F_{c}=mg

\mu m \omega_{min}^{2}r=mg

\therefore\ \omega_{min}=\sqrt{\frac{g}{\mu r}}

 

- wherein

F = friction force

Fc = centrifugal force

Wmin = minimum angular velocity

\mu=coefficient of friction

r = radius of Rotor

 

 

 

 

N= mw^{2}R\: \: \: \: \: \: \: f_{s}=\mu N= \mu mw^{2}R

For Resting position of person

: f_{s}=mg\Rightarrow \mu m^{2}R=mg

\mu \omega ^{2}R=g

\omega ^{2}= \frac{g}{\mu R}\Rightarrow \frac{10}{0.2\times 2}= 25

\omega = 5rad/sec

 

Posted by

avinash.dongre

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