A man places a chain (of mass m and length l) on a table slowly. Initially, the lower end of the chain just touches the table. The man brings down the chain by length l/2. Work done by the man in this process is

Answers (1)

@Mannika

centre of mass of both cases are at a distance l/2 and l/4 respectively

W = (m/2)g(l/4) -  mg(l/2)

W = - (3/8)mgl

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