A man weight 60 kg is standing on a lift and the lift is moving downwards with an acceleration that is equal to the gravitational acceleration; The apparent weight of the man is
0
500 N
980 N
100 N
Acceleration due to gravity = acceleration of the lift =
Force in the downward direction and Upward direction will satisfy this equation
apparent weight =Mg' = M(g-a) here g=a
Therefore apparent weight will be zero
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