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  • A massless square loop, of wire of resistance 10Ω, supporting a mass of 1 g, hangs vertically with one of its sides in a uniform magnetic field of 103G, directed outwards in the sh

A massless square loop, of wire of resistance 10Ω, supporting a mass of 1 g, hangs vertically with one of its sides in a uniform magnetic field of 103G, directed outwards in the shaded region. A dc voltage V is applied to the loop. For what value of V, the magnetic force will exactly balance the weight of the supporting mass of 1 g ?
(If sides of the loop = 10 cm, g=10 ms^{-2} )

Option: 1

\frac{1}{10} \mathrm{~V}


Option: 2

100 \mathrm{~V}


Option: 3

10 \mathrm{~V}


Option: 4

1 \mathrm{~V}


Answers (1)

best_answer

\begin{aligned} & \mathrm{B}=10^3 \mathrm{G}=0.1 \mathrm{~T}, \\ & \mathrm{~m}=1 \mathrm{~g} \\ & \mathrm{~F}_{\mathrm{m}}=\mathrm{mg} \\ & I \ell \mathrm{B}=\mathrm{mg} \\ & \frac{\mathrm{V}}{\mathrm{R}}(0.1)(0.1)=\frac{1}{1000} \times 10 \\ & \frac{\mathrm{V}}{100 \mathrm{R}}=\frac{1}{100} \\ & \frac{\mathrm{V}}{10}=1 \Rightarrow \mathrm{V}=10 \mathrm{Volt} \end{aligned}

 

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Pankaj

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