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  • A metal foil of negligible thickness is introduced between two plates of a capacitor at the center. The original capacitance of the capacitor is <img alt="\text { 'Co'. }" src="https://entranc

A metal foil of negligible thickness is introduced between two plates of a capacitor at the center. The original capacitance of the capacitor is \text { 'Co'. }. Determine the new capacitance of the capacitor with the metal foil inserted.

Option: 1

\mathrm{C}_0


Option: 2

2 \mathrm{C}_0


Option: 3

0.5 \mathrm{C}_{\circ}


Option: 4

4 \mathrm{C}_{\circ}


Answers (1)

best_answer

Capacitance of parellel plate capacitor with a dielectric slab of thickness t inside is given by:

C=\frac{A \epsilon_0}{(d-t)+\frac{t}{K}}

where \mathrm{K} is the dielectric constant. 

When aluminum sheet of negligible thickness is inserted, then thickness of slab t \rightarrow 0 and value of \mathrm{K} for metal (conductor) will be \infty

\text { So, } \mathrm{C}=\frac{\mathrm{A} \epsilon_0}{\mathrm{~d}}

Hence, capacitance of capacitor will remains unchanged. 

Therefore, option (A) is the correct answer. 

Posted by

Gunjita

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