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A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 \mathrm{~mol} of it is _________ \times 10^{21} (Nearest integer). ( Given \mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23} )

Option: 1

36


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

One unit cell of hcp contains =18 voids

No. of voids in 0.02 \mathrm{~mol} of hcp
$$ \begin{aligned} & \frac{18}{6} \times 6.02 \times 10^{23} \times 0.02 \\ & \approx 3.6 \times 10^{22} \\ & \approx 36 \times 10^{21} \end{aligned}

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rishi.raj

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