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A metal has a work function of 2.5 eV. What is the minimum wavelength of electromagnetic radiation that can cause photoelectric emission?

Option: 1

500 nm


Option: 2

 496 nm


Option: 3

490 nm


Option: 4

 485 nm


Answers (1)

best_answer

The minimum wavelength of electromagnetic radiation that can cause photoelectric emission is given by the equation \lambda _{0}= hc/\phi, where h is Planck's constant, c is the speed of light, and \phi is the work function of the metal. Substituting the given value, we get
\lambda _{0}= hc/\phi= \left ( 6.626\times 10^{-34}Js \right )\left ( 3\times 10^{8}m/s \right )/\left ( 2.5eV \right )= 485 nm

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Devendra Khairwa

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