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A metal has a work function of 4.2 eV. What is the maximum kinetic energy of an electron emitted when electromagnetic radiation with a frequency of 2.0\times10^{15}Hz is incident on the metal surface?

Option: 1

0.8 eV


Option: 2

1.4 eV


Option: 3

4 eV


Option: 4

2.8 eV


Answers (1)

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The maximum kinetic energy \left (K_{max} \right ) of an emitted electron is given by K_{max}= h\nu-\phi, where h is Planck's constant,  \nu is the frequency of the incident radiation, and \phi is the work function of the metal. Substituting the given values, we
\\K_{max}= \left ( 6.626\times 10^{-34}Js \right )\left ( 2.0\times 10^{15}Hz \right )-\left ( 4.2eV \right )\\ K_{max}= 4 \ eV.

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