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  • A metal surface has a work function of 3.2 eV. What is the wavelength of the incident radiation required for photoelectric emission to occur?Option: 1 <

A metal surface has a work function of 3.2 eV. What is the wavelength of the incident radiation required for photoelectric emission to occur?

Option: 1

350 nm


Option: 2

390 nm


Option: 3

460 nm


Option: 4

520 nm


Answers (1)

best_answer

The wavelength of the incident radiation required for photoelectric emission is given by the equation \lambda _{0}= hc/\phi, where h is Planck's constant, c is the speed of light, and \phi  is the work function.
 Substituting the given values, we get
\lambda _{0}= \left ( 6.626\times 10^{-34}Js \right )\left ( 3.00\times 10^{8}m/s \right )/\left ( 3.2eV \right )\left ( 1.6\times10^{-19}J/eV \right )= 390 nm

Posted by

Divya Prakash Singh

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