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A metaliic conductor of length \mathrm{1m} rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity \mathrm{5\, rad\, s^{-1}}. If the horizontal component of earth's magnetic field is \mathrm{0.2\times 10^{-4}T}, then emf induced between the two end of the conductor is :

Option: 1

\mathrm{5\mu v}


Option: 2

\mathrm{50\mu v}


Option: 3

\mathrm{5m v}


Option: 4

\mathrm{50m v}


Answers (1)

best_answer


emf induced between the two ends of the conductors is
\mathrm{e= \frac{1}{2}B\omega\, l^{2}}
     \mathrm{= \frac{2\times10^{-5}\times 5 \times 1}{2}}
      \mathrm{= 5\times 10^{-5}}
 \mathrm{\Rightarrow e= 50 \mu v}

The correct option is (2)  

Posted by

chirag

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