A metallic wire of length 2.5 meters and diameter 0.8 mm is subjected to a tensile force of 800 N, causing it to elongate by 2.2 mm. The density of the material of the wire is 7.8 g/cm3. Calculate Young's modulus of elasticity of the material of the wire.
9.5 * 1010 N/m2
1.2 * 1011 N/m2
2.4 * 1011 N/m2
3.6 * 1011 N/m2
Young’s modulus (Y) is a measure of the stiffness of a material. It is defined as the ratio of stress () to strain () and is given by the formula:
where, Stress () = Force / Area
Strain () = Change in length / Original length
Given data:
Original length (L) = 2.5 m
Diameter (d) = 0.8 mm
Tensile force (F) = 800 N
Elongation (L) = 2.2 mm
Density () = 7.8 g/cm3
First, let's calculate the cross-sectional area (A) of the wire using its diameter:
Now, convert the diameter to meters and calculate the area:
Next, calculate the strain () using elongation and original length:
Convert elongation to meters and calculate strain:
Now, calculate stress () using the formula:
= F / A
Substitute the given values:
Finally, calculate Young's modulus (Y) using the formula:
Substitute the calculated values for stress and strain:
Solve for Y, and you'll find that the value is approximately 1.2 * 1011 N/m2.
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