Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A metre scale is balanced on a knife edge at its centre. When two coins, each of mass

A metre scale is balanced on a knife edge at its centre. When two coins, each of mass \mathrm{10\, g} are put one on the top of the other at the \mathrm{10.0\, cm} mark the scale is found to be balanced at \mathrm{40.0\, cm} mark. The mass of the metre scale is found to be \mathrm{x\times 10^{-2}kg}. The value of \mathrm{x} is __________.

Option: 1

6


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)



Let the mass of metre scale &
Coin be M and m respectively.

For scale to be balanced ,
\mathrm{\Sigma F= 0\; and\; \Sigma \tau = 0}

R is the reaction force on a knife edge
\mathrm{\Sigma F= 0}
\mathrm{R= 2mg+Mg}
\mathrm{\Sigma \tau = 0}

about knife edge
\mathrm{\left ( 2\, mg \right )\left ( 30 \right )\left ( \leftarrow \right )+Mg\times 10\left ( \rightarrow \right )= 0}
\mathrm{m= \frac{M}{6}\Rightarrow M= 6M}
   \mathrm{= 609}
\mathrm{M= 6\times 10^{-2}kg}

\mathrm{\therefore x= 6}
 

Posted by

Ramraj Saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: 2nd attempt? Mistakes to avoid, tips to improve score, percentile
anam-khan

JEE Main 2025: What to expect on exam day? Section-wise paper pattern, marking scheme, last-minute tips
anam-khan

JEE Main 2025 Live: NTA JEE session 2 exams from tomorrow; updates on admit card, exam pattern, passing marks

Latest Question