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A mixture of hydrogen and oxygen has volume $\mathrm{2000cm^{3}}$ , temperature $\mathrm{300K}$ , pressure $\mathrm{100kPa}$ and mass $\mathrm{0.76g}$ . The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be :

[ Take gas constant $\mathrm{R=8.3JK^{-1}mol^{-1}}$ ]
Option: 1
$\mathrm{\frac{1}{3}}$

Option: 2
$\mathrm{\frac{3}{1}}$

Option: 3
$\mathrm{\frac{1}{16}}$

Option: 4
$\mathrm{\frac{16}{1}}$

Answers (1)

best_answer

$\mathrm{P V=n R T }\\$

$\mathrm{100 \times 10^{3} \times 2000 \times 10^{-6}=n \times 8.3 \times 300} \\$

$\mathrm{n=\frac{2}{25}}$

Let $\mathrm{n_{1} }\\$ moles of hydrogen

$\mathrm{n_{2} }\\$ moles of oxygen

$\mathrm{n_{1}+n_{2}=\frac{2}{25}}\\$ .............(1)

$\mathrm{n_{1} \times 2+n_{2} \times 32=0.76=\frac{19}{25}}$ ..........(2)

The solving (1) and (2)

$\mathrm{n_{1}=0.06} \\$

$\mathrm{n_{2}=0.02} \\$

$\mathrm{\frac{n_{1}}{n_{2}}=\frac{0.06}{0.02}=3}$

Hence the correct answer is option 2.

Posted by

Irshad Anwar

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