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  • A mixture of one mole each of H2, He, and O2 each are enclosed in a cylinder of volume V at temperature T. If the partial pressure of H2 is 2 atm,the total pressure of the gases in the cylinder is

A mixture of one mole each of H2, He, and O2 each are enclosed in a cylinder of volume V at temperature T. If the partial pressure of H2 is 2 atm,the total pressure of the gases in the cylinder is :
Option: 1 6 atm
Option: 2 38 atm
Option: 3 14 atm
Option: 4 22 atm

Answers (1)

best_answer

According to Dalton's law of partial pressure 

\mathrm{p}_{\mathrm{i}}=\mathrm{x}_{\mathrm{i}} \times \mathrm{P}_{\mathrm{T}}

Where

\mathrm{p}_{\mathrm{i}}=\text { partial pressure of the } \mathrm{i}^{\text {th }} \text { component }

\mathrm{x}_{\mathrm{i}}=\text { mole fraction of the } \mathrm{i}^{\text {th }} \text { component }

\mathrm{p}_{\mathrm{T}}=\text { total pressure of mixture }

\Rightarrow 2 \mathrm{~atm}=\left(\frac{\mathrm{n}_{\mathrm{H}_{2}}}{\mathrm{n}_{\mathrm{H}_{2}}+\mathrm{n}_{\mathrm{H}{\mathrm{e}}}+\mathrm{n}_{\mathrm{O}_{2}}}\right) \times \mathrm{p}_{\mathrm{T}}

\Rightarrow \mathrm{p}_{\mathrm{T}}=2 \mathrm{~atm} \times \frac{3}{1}=6 \mathrm{~atm}

Posted by

Kuldeep Maurya

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