Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A modulating signal <img alt="\mathrm{2 \sin \left(6.28 \times 10^{\circ}\right) t}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B2%20%5Csin%20%5Cleft%286.28%20%5Ctimes%2010%5E%

A modulating signal \mathrm{2 \sin \left(6.28 \times 10^{\circ}\right) t} is added to the carrier signal \mathrm{4 \sin \left(12.56 \times 10^{9}\right) t} for amplitude modulation. The combined signal is passed through a non-linear square law device. The output is then passed through a band pass filter. The bandwidth of the output signal of band pass filter will be_______\mathrm{ MHz.}

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{\omega_m=6.28 \times 10^6 =2 \pi f_m }

\mathrm{f_m =10^6 \mathrm{~Hz} }

\mathrm{\omega_c=12.56 \times 10^9 =2 \pi f_c }

\mathrm{f_c =2 \times 10^9 \mathrm{~Hz} }

    \mathrm{=2000 \times 10^6 \mathrm{~Hz}}

Bandwidth of the output signal

\mathrm{=\left(f_c+f_m\right)-\left(f_c-f_m\right)=2 f_m }

\mathrm{=2 \times 10^6 \mathrm{H}_2 }

\mathrm{=2 \mathrm{MH}_z}




 

Posted by

Pankaj Sanodiya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: Most important chapters for physics, chemistry, mathematics to score good marks
anam-khan

JEE Main 2025 session 2 dates clash with ISC, PSEB 12th exams; no impact on major science subjects
anam-khan

Delhi police EOW books FIITJEE for fraud; 192 complaints filed

Latest Question