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A molecule undergoes two independent first order reactions whose respective half lives are \mathrm{24 \mathrm{~min} \, \, and\, \, 2 \mathrm{~min}.} If both the reactions are occurring then the time taken for the 50% consuption of the reactant is _min

Option: 1

 2.97 minutes
 


Option: 2

 1.50 minutes
 


Option: 3

3.6 minutes
 


Option: 4

1.84 minutes


Answers (1)

best_answer

 for a parallel Reaction 

When adding the rate constant of the two reactions, we need to use the formula for combining rate constants of two reactions in parallel, which is
\mathrm{k=k_1+k_2 }
Where  \mathrm{k_1 } and  \mathrm{k_2 } are the rate constant of the indvidual 
\mathrm{\begin{aligned} & \frac{1}{t 1 / 2}=\frac{1}{24}+\frac{1}{2}=\frac{1+12}{24}=\frac{13}{24} \\ & \text { Net } t_{1 / 2}=\frac{24}{13}=1.84 \text { minutes } \end{aligned} }

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Shailly goel

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