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A monochromatic light is incident on a hydrogen sample in ground state. Hydrogen atoms absorb a fraction of light and subsequently emit radiation of six different wavelengths. The frequency of incident light is \mathrm{x\times 10^{15}Hz}. The value of x is _______.
(Given \mathrm{h=4.25\times 10^{-15}eVs})
 

Option: 1

3


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Total emission lines = 6 (given)
So electron absorbed energy and jump from n = 1 to n = 4

\begin{aligned} & \Delta \mathrm{E}= 13.6\left[\frac{\ell}{\ell^2}-\frac{1}{4^2}\right] \mathrm{ev} \\ & =13.6\left[1-\frac{1}{16}\right] \mathrm{ev} \\ & \Delta \mathrm{E}=\mathrm{hf} \\ \end{aligned}

\begin{aligned} & 12.75=4.5 \times 10^{-15}, \\ & \mathrm{f}=\frac{12.75}{4.25} \times 10^{15}=3 \times 10^{15} \mathrm{~Hz} \\ & \mathrm{x}=3 \text { Ans. } \end{aligned}

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Rishabh

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