Get Answers to all your Questions

header-bg qa

A pair of adjacent coils has a mutual inductance of 2.5 H. If the current in one coil changes from 0 to 40 A in 0.8s, then the change in flux linked with the other coil is:

Option: 1

100 Wb


Option: 2

120 Wb


Option: 3

200 Wb


Option: 4

250 Wb


Answers (1)

best_answer

\mathrm{Given, \mathrm{M}=2.5 \mathrm{H} ; \frac{\mathrm{dI}}{\mathrm{dt}}=\frac{40-0}{0.8}=50 \mathrm{As}^{-1}}

\mathrm{Also, \varepsilon=\mathrm{M} \frac{\mathrm{dI}}{\mathrm{dt}}=\frac{\mathrm{d} \phi}{\mathrm{dt}}}

\mathrm{Or\; \mathrm{\mathrm{d} \phi=\mathrm{MdI}=2.5(40-0)=100 \mathrm{~Wb} }}

Posted by

Kshitij

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE