Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A parallel circuit consists of three resistors R1, R2, and R3 connected in parallel to a constant voltage source of 36V. The currents flowing through each resistor

A parallel circuit consists of three resistors R1, R2, and R3 connected in parallel to a constant voltage source of 36V. The currents flowing through each resistor are measured and recorded:

Resistor Current (A)
R1 1.5
R2 2.0
R3 2.5

Using this data, calculate the equivalent resistance of the entire parallel circuit.

Option: 1

88 \Omega


Option: 2

66 \Omega


Option: 3

24 \Omega


Option: 4

50 \Omega


Answers (1)

best_answer

In a parallel circuit, the reciprocal of the total resistance (1/ Req) is the sum of the reciprocals of the individual resistances:

                \frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}

Let’s use the provided data points to calculate the equivalent resistance:

Resistor Current (A)
R1 1.5
R2 2.0
R3 2.5

We’ll use Ohm’s law to find the resistance of each resistor:

                    R = \frac{V}{I}

where V is the constant voltage (36V) and I is the current.

                    R_{1} = \frac{36}{1.5} = 24 \Omega

                    R_{2} = \frac{36}{2.0} = 18 \Omega

                    R_{3} = \frac{36}{2.5} = 14.4 \Omega

Now, calculate the equivalent resistance:

            \frac{1}{R_{eq}} = \frac{1}{24} + \frac{1}{18} + \frac{1}{14.4} = 0.0417 \Omega

Taking the reciprocal:

                    R_{eq} = \frac{1}{0.0417} = 24 \Omega

 

Hence, the equivalent resistance of the entire parallel circuit is 24 \Omega.

Posted by

Gautam harsolia

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Marks vs Percentile 2025: How many marks do you need to score 95+ percentile?
anam-khan

JEE Main 2025 session 1 official answer key out; challenge by February 6; how to calculate NTA score?
anam-khan

JEE Main 2025: NIT Raipur's CSE cut-offs drop; closing ranks in popular branches

Latest Question