Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A particle executes S.H.M with amplitude 'a' and time period 'T'. The displacement of the particle when its speed is half of the maximum speed is <img alt="\frac{\sqrt{x}a}{2}" src="https://entrancecorner.codecogs.com/gif.latex?%5C

A particle executes S.H.M with amplitude 'a' and time period 'T'. The displacement of the particle when its speed is half of the maximum speed is \frac{\sqrt{x}a}{2}. The value of x is _________
Option: 1 3
Option: 2 6
Option: 3 1
Option: 4 5

Answers (1)

best_answer

\begin{array}{l} \mathrm{V}=\omega \sqrt{\mathrm{A}^{2}-\mathrm{x}^{2}} \quad \mathrm{~V}_{\max }=\mathrm{A\omega} \\ \\ \frac{\mathrm{A} \omega}{2}=\omega \sqrt{\mathrm{A}^{2}-\mathrm{x}^{2}} \\ \\ \frac{\mathrm{A}^{2}}{4}=\mathrm{A}^{2}-\mathrm{x}^{2} \\ \\ \mathrm{x}^{2}=\frac{3 \mathrm{~A}^{2}}{4} \\\\ \mathrm{x}=\frac{\sqrt{3}}{2} \mathrm{~A} \end{array}

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JAC Chandigarh Counselling 2025: Round 1 seat allotment result out for BTech admissions
anam-khan

JoSAA round 5 seat allotment result 2025 out on josaa.nic.in
anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today

Latest Question