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  • A particle having charge a enters a region of uniform magnetic field  (directed inwards) and is deflect

A particle having charge a enters a region of uniform magnetic field \vec{B} (directed inwards) and is deflected distance x after traveling a distance y. The Magnitude of the momentum of the particle is:-

Option: 1

\frac{q B y}{2}


Option: 2

\frac{q B y}{x}


Option: 3

\frac{a B}{2}\left(\frac{y^2}{x}+x\right)


Option: 4

\frac{a B y^2}{2 x}


Answers (1)

best_answer

\begin{aligned} 2 R \sin \theta & =\sqrt{y^2+x^2} \\ \frac{2 R x}{\sqrt{y^2+x^2}} & =\sqrt{y^2+x^2} \\ \frac{2 P}{q B} & =\frac{y^2+x^2}{x} \\ P & =\frac{q B}{2}\left(\frac{y^2}{x}+x\right) \end{aligned}

where P is the momentum

Posted by

sudhir.kumar

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