Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • a particle is moving with velocity v=k[yi+xj] where k is constant the general equation for its path is

A particle is moving with velocity v=k[yi+xj] where k is constant the general equation for its path is

(a) y = x2 + constant

(b)  y2 = x + constant

(c)  xy = constant

(d) y2 = x2 + constant

Answers (1)

\frac{\mathrm{d} x}{\mathrm{d} t} = ky ..... (1)

\frac{\mathrm{d} y}{\mathrm{d} t} = kx......(2)

divide eq 2 by 1

\frac{\mathrm{d} y}{\mathrm{d} x} = \frac{x}{y}

y\mathrm{d}y = x\mathrm{d}x

\int y\mathrm{d}y = \int x\mathrm{d}x

\Rightarrow y^{2} -x^{2}= c

Posted by

lovekush

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus
anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change

Latest Question