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A particle of charge q and mass m moves in a circular orbit of radius r in a region of uniform magnetic field B. The magnitude
of the angular momentum of the particle about the centre of the circle is.

Option: 1

\mathrm{q B r^2}


Option: 2

\mathrm{m q B r}


Option: 3

\mathrm{q B r}


Option: 4

\mathrm{m q B r^2}


Answers (1)

best_answer

The magentic force provides the necessary centripetal force. Therefore,
\mathrm{ q v B=\frac{m v^2}{r} \Rightarrow m v=q B r }
Linear momentum \mathrm{ p=m v=q B r }
Angular momentum \mathrm{ l=p r=q B r^2 }
So the correct choice is (1).

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manish painkra

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