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A particle of mass 250 \mathrm{~g} executes a simple harmonic motion under a periodic force \mathrm{F}=(-25 x) \mathrm{N}. The particle attains a maximum speed of 4 \mathrm{~m} \mathrm{s} during its oscillation. The amplitude of the motion is  _______________ \mathrm{cm}.

Option: 1

40


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & F=m a \\ & -25 x=\frac{250}{100} a \\ & a=-100 x \\ & \omega^2=100 \\ & \omega=100 \\ & A \omega=4 \\ & A=\frac{4}{10}=0.4 \mathrm{~m} \\ & A=40 \mathrm{~cm} \end{aligned}

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