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  • A person stands in contact against the inner wall of a rotor of radius r. The coefficient of friction between the wall and the clothing is μ and the rotor is rotating about a vertical

A person stands in contact against the inner wall of a rotor of radius r. The coefficient of friction between the wall and the clothing is μ and the rotor is rotating about a vertical axis. What is the minimum angular speed of the rotor so that the person does not slip downward?

Option: 1

\sqrt{\frac{g}{\mu r}}


Option: 2

\sqrt{\frac{g}{\mu}}


Option: 3

\sqrt{\frac{2g}{\mu r}}


Option: 4

\sqrt{\frac{1}{\mu r}}


Answers (1)

For the circular motion of the person

N=mr\omega^2  ............(1)

Now for the vertical motion of the person

f=f_{max}=\mu N ............(2)

f=\mu mr\omega^2

We also know f = mg

\mu mr\omega^2=mg

\omega=\sqrt{\frac{g}{\mu r}}

Posted by

Kshitij

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