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A physical quantity P depends on the other two physical quantities Q and R, as follows 

P = a Q^2 R^{1/2}  Where a is constant. In an experiment, the quantity Q is determined by measuring P and R and using the above expression. If the percentage of error in measurement of P and R is 10 % and 12 % respectively, Then the percentage of error in determining the value of Q is 

Option: 1

8


Option: 2

2


Option: 3

5


Option: 4

10


Answers (1)

best_answer

 Given P = a Q ^2 R^{ 1/2}

Q=\frac{P^\frac{1}{2}}{a^\frac{1}{2}R^\frac{1}{4}}

\frac{\Delta Q}{Q} *100=\frac{1}{2} \frac{\Delta P }{P} *100+ \frac{1}{4} \frac{\Delta R}{R} *100

given, \frac{\Delta P }{P} *100=10 and \frac{\Delta R}{R} *100=12

\text{percentage error} \: \: in \: \: Q \Rightarrow \frac{\Delta Q}{Q} *100=\frac{10}{2}+\frac{12}{4}=8

 

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manish

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