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A pizza restaurant offers 6 different toppings, and a customer can choose up to 4 toppings for their pizza. How many different pizzas can be ordered?

Option: 1

57


Option: 2

58


Option: 3

59


Option: 4

60


Answers (1)

best_answer

We can use the combination formula to solve this problem.
(The number of pizzas with no toppings) or (The number of pizzas with one topping) or
(The number of pizzas with two toppings) or (The number of pizzas with three toppings) or (The number of pizzas with four toppings)
\mathrm{\begin{aligned} & { }^6 C_0+{ }^6 C_1+{ }^6 C_2+{ }^6 C_3+{ }^6 C_4 \\ \end{aligned} }

\mathrm{\begin{aligned} = & 1+6+15+20+15 \\ = & 57 \text { ways } \end{aligned} }

Posted by

sudhir.kumar

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