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  • A point charge of is placed at the origin. At what location on the <img alt="X" src="https://entrancecorner.o

A point charge of 10\mu C is placed at the origin. At what location on the X-axis should a point charge of
40\mu C be placed so that the net electric field is zero at x = 2 cm on the X-axis?

Option: 1

x = -4 cm


Option: 2

x = 6 cm


Option: 3

x = 4 cm


Option: 4

x = 8 cm


Answers (1)

best_answer


\begin{aligned} & \mathrm{E}_1=\mathrm{E}_2 \\ & \frac{\mathrm{K} \times 10}{(2)^2}=\frac{\mathrm{K} \times 40}{4^2} \\ & \mathrm{r}=4 \mathrm{~cm} \end{aligned}
Distance from origin = 2+4= 6 cm

Posted by

sudhir.kumar

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