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  • A point source of light is placed at the centre of curvature of a hemispherical surface. The source emits a power of 24 W. The radius of curvature of hemisphere is 10 cm and the inner surface is co

A point source of light is placed at the centre of curvature of a hemispherical surface. The source emits a power of 24 W. The radius of curvature of hemisphere is 10 cm and the inner surface is completely reflecting. The force on the hemisphere due to the light falling on it is _____ 10^{-8}N

Option: 1

4


Option: 2

__


Option: 3

__


Option: 4

__


Answers (1)

best_answer

Presses due to completely reflecting surface = \frac{2I}{C}

Net \ \ force =\frac{2I}{C} Area\\ Now \ \ I =\frac{\text { Power }}{\text { Area }}=\frac{\text { Power }}{4 \pi \mathrm{r}^2}

\text { From } F_{\text {net }}=\frac{2 I}{C} \times \text { Projected Area }

\begin{aligned} & F_{\text {net }}=\frac{2}{C} \times \frac{\text { Power }}{4 \pi r^2} \times \pi r^2 \\ & F_{\text {net }}=\frac{2 \times 24}{3 \times 10^8 \times 4}=4 \times 10^{-8} \end{aligned}

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Divya Prakash Singh

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