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A potential barrier of 0.5 V exists across a p - n junction. If the width of depletion layer is \mathrm{10^{-6}m}, the intensity of electric field in this region will be:

Option: 1

1 \times 10^6 \mathrm{~V} / \mathrm{m}


Option: 2

5 \times 10^5 \mathrm{~V} / \mathrm{m} \quad


Option: 3

4 \times 10^4 \mathrm{~V} / \mathrm{m} \quad


Option: 4

None of these


Answers (1)

\mathrm{E=\frac{V}{d}=\frac{0.5}{10^{-6}}=5 \times 10^5 \mathrm{~V} / \mathrm{m}}

Posted by

Sumit Saini

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