Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A potential difference of  is applied between the opposite faces of a Ge crystal plate

A potential difference of 2 \mathrm{~V} is applied between the opposite faces of a Ge crystal plate of area 1 \mathrm{~cm}^2 and thickness0.5 \mathrm{~mm}. If the concentration of electrons in G eis  2 \times 10^{19} / \mathrm{m}^3 and mobilities of electrons and holes are0.36 \frac{\mathrm{m}^2}{\text { volt-s }}\, \, and\,\, 0.14 \frac{\mathrm{m}^2}{\text { volt-s }} respectively, then the current flowing through the plate will be

Option: 1

0.25 A


Option: 2

0.45 A


Option: 3

0.56 A


Option: 4

0.64 A


Answers (1)

best_answer

\mathrm{\begin{aligned} & \sigma=n e\left(\mu_e+\mu_h\right)=2 \times 10^{19} \times 1.6 \times 10^{-19}(0.36+0.14) \\ & =1.6(\Omega-m)^{-1} \\ & R=\rho \frac{l}{A}=\frac{l}{\sigma A}=\frac{0.5 \times 10^{-3}}{1.6 \times 10^{-4}}=\frac{25}{8} \Omega \\ & \therefore i=\frac{V}{R}=\frac{2}{25 / 8}=\frac{16}{25} \mathrm{~A}=0.64 \mathrm{~A} \end{aligned} }

Posted by

Irshad Anwar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE aspirant in Kota commits suicide; 16th suicide since January
anam-khan

JEE Main 2025 Registration Live: NTA session 1 application last date today; official website, syllabus
anam-khan

JEE Main 2025 session 1 registration ends today at jeemain.nta.nic.in; application correction from November 26

Latest Question