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  • A potential Vo is applied across a uniform wire of resistance R. The power dissipation is P1. The wire is then cut into two equal halves and a potential of Vo is ap

A potential Vo is applied across a uniform wire of resistance R. The power dissipation is P1. The wire is then cut into two equal halves and a potential of Vo is applied across the length of each half. The total power dissipation across two wires is P2. The ratio P_2: P_1 \text { is } \sqrt{x}: 1 the value of x is ____________

Option: 1

16


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

     \mathrm{P}_1=\frac{\mathrm{v}_0^2}{\mathrm{R}}

\begin{aligned} & \mathrm{P}_2=\frac{\mathrm{v}_0^2}{\left(\frac{\mathrm{R}}{2}\right)}+\frac{\mathrm{v}_0^2}{\left(\frac{\mathrm{R}}{2}\right)} \\ & \mathrm{P}_2=4 \mathrm{P}_1 \\ & \frac{\mathrm{P}_2}{\mathrm{P}_1}=\frac{4}{1}=\frac{\sqrt{\mathrm{x}}}{1} \\ & \mathrm{x}=16 \end{aligned}

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