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A potentiometer arrangement is shown in the figure. Deriving cell has e.m.f. e and internal resistance r

Resistance of potentiometer wire A B is R . F is the cell of e.m.f. \frac{e}{3} and internal resistance \frac{r}{3}. Balance points (J) can be obtained for all finite values of

Option: 1

\mathrm{R>\frac{r }{2}}


Option: 2

\mathrm{ R<\frac{r }{2}}


Option: 3

\mathrm{ R>\frac{r }{3}}


Option: 4

\mathrm{ R<\frac{r }{3}}


Answers (1)

best_answer

Current in A B=\mathrm{I=\frac{e}{R+r}}

p.d. across A B=\mathrm{I R=\frac{e R}{R+r}}

to obtain balanced point: \mathrm{\frac{e R}{R+r}>\frac{e}{3} \Rightarrow R>\frac{r}{2}}

Posted by

Deependra Verma

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