-
Engineering and Architecture
Exams
Colleges
Predictors
Resources
-
Computer Application and IT
Quick Links
Colleges
-
Pharmacy
Colleges
Resources
-
Hospitality and Tourism
Colleges
Resources
Diploma Colleges
-
Competition
Other Exams
Resources
-
School
Exams
Top Schools
Products & Resources
-
Study Abroad
Top Countries
Student Visas
-
Arts, Commerce & Sciences
Exams
Colleges
Upcoming Events
Resources
-
Management and Business Administration
Colleges & Courses
Predictors
-
Learn
Online Courses
Engineering Preparation
Medical Preparation
-
Online Courses and Certifications
Top Streams
Specializations
- Digital Marketing Certification Courses
- Cyber Security Certification Courses
- Artificial Intelligence Certification Courses
- Business Analytics Certification Courses
- Data Science Certification Courses
- Cloud Computing Certification Courses
- Machine Learning Certification Courses
- View All Certification Courses
Resources
-
Medicine and Allied Sciences
Colleges
Predictors
Resources
-
Law
Resources
Colleges
-
Animation and Design
Exams
Predictors & Articles
Colleges
Resources
-
Media, Mass Communication and Journalism
Exams
Colleges
Resources
-
Finance & Accounts
Top Courses & Careers
Colleges
Get Answers to all your Questions
- Home
- Engineering
- A precision experiment requires the measurement of the diameter of a small spherical object using a screw gauge. The main scale reading is 4 mm, and the circular scale reading is 34. The pitch of t
A precision experiment requires the measurement of the diameter of a small spherical object using a screw gauge. The main scale reading is 4 mm, and the circular scale reading is 34. The pitch of the screw gauge is 0.2 mm, and the least count of the instrument is 0.005 mm. The object is placed between the screw and the anvil, and the screw is turned until it just touches the object. Determine the diameter of the spherical object.
1.542 mm
0.834 mm
2.542 mm
0.546 mm
Answers (1)
Given values:
Main scale reading (M) = 4 mm
Circular scale reading (C) = 34
Pitch of the screw gauge (P) = 0.2 mm
Least count (LC) = 0.005 mm
The total reading of the screw gauge can be calculated by adding the main scale reading to the product of the circular scale reading and the least count:
Total reading = M + (C * LC)
Step 1: Calculate the total reading of the screw gauge:
Total reading = 4 mm + (34 * 0.005 mm) = 4 mm + 0.17 mm = 4.17 mm
The distance moved by the screw while making contact with the spherical object is the diameter of the object. Therefore, the diameter of the spherical object can be calculated using the formula:
Diameter = Total reading * P
Step 2: Calculate the diameter of the spherical object:
Diameter = 4.17 mm * 0.2 mm = 0.834 mm
The diameter of the spherical object is 0.834 mm.
JEE Main high-scoring chapters and topics
Study 40% syllabus and score up to 100% marks in JEE
Similar Questions
-
5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C. If Na2SO4 is 81.5% ionised, the value of x (K
A capacitor is made of two square plates each of side 'a' making a very small angle
-
A solution of m-chloroaniline, m-chlorophenol and m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO3 to give fraction A. The leftover organic phase was extracted with d
Trending Articles/News
Latest Question
- A sum of money under compound interest doubles itself in 4 years. In how many years will it become 16 times itself? Option: 1 1
- A certain loan amounts, under compound interest, compounded annually earns an interest of Rs.1980 in the second year and Rs.2178 in the third year. How much interest did it earn in the first year?<
