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- A precision experiment requires the measurement of the diameter of a small spherical object using a screw gauge. The main scale reading is 4 mm, and the circular scale reading is 34. The pitch of t
A precision experiment requires the measurement of the diameter of a small spherical object using a screw gauge. The main scale reading is 4 mm, and the circular scale reading is 34. The pitch of the screw gauge is 0.2 mm, and the least count of the instrument is 0.005 mm. The object is placed between the screw and the anvil, and the screw is turned until it just touches the object. Determine the diameter of the spherical object.
1.542 mm
0.834 mm
2.542 mm
0.546 mm
Answers (1)
Given values:
Main scale reading (M) = 4 mm
Circular scale reading (C) = 34
Pitch of the screw gauge (P) = 0.2 mm
Least count (LC) = 0.005 mm
The total reading of the screw gauge can be calculated by adding the main scale reading to the product of the circular scale reading and the least count:
Total reading = M + (C * LC)
Step 1: Calculate the total reading of the screw gauge:
Total reading = 4 mm + (34 * 0.005 mm) = 4 mm + 0.17 mm = 4.17 mm
The distance moved by the screw while making contact with the spherical object is the diameter of the object. Therefore, the diameter of the spherical object can be calculated using the formula:
Diameter = Total reading * P
Step 2: Calculate the diameter of the spherical object:
Diameter = 4.17 mm * 0.2 mm = 0.834 mm
The diameter of the spherical object is 0.834 mm.
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