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  • A radiation is emitted by 1000 W bulb and it generates an electric field and magnetic field at P, placed at a distance of 2 m. The efficiency of the bulb is 1.25 %. The value of peak electric field at P is <img alt="x \times 10^{-1}V/m." src="https://e

A radiation is emitted by 1000 W bulb and it generates an electric field and magnetic field at P, placed at a distance of 2 m. The efficiency of the bulb is 1.25 %. The value of peak electric field at P is x \times 10^{-1}V/m. Value of x is ________.(Rounded off to the nearest integer) [Take \varepsilon _{0}=8.85\times 10^{-12}C^{2}N^{-1}m^{-2}, c=3\times 10^{8}ms^{-1}]
Option: 1 283
Option: 2 137
Option: 3 765
Option: 4 342

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\begin{array}{l} \mathrm{I}_{\mathrm{avg}}=\frac{1}{2} \varepsilon_{0} \mathrm{E}_{0}^{2} \mathrm{C} \\ \\ \frac{1.25}{100} \times \frac{1000}{4 \pi(2)^{2}}=\frac{1}{2} \times 8.85 \times 10^{-12} \times 3 \times 10^{8} \times \mathrm{E}_{0}^{2} \\ \\ \mathrm{E}_{0}^{2}=187.4 \\ \\ \therefore \mathrm{E}_{0}=13.689 \mathrm{~V} / \mathrm{m} \\ \\ =136.89 \times 10^{-1} \mathrm{~V} / \mathrm{m} \\ \\ \therefore \mathrm{x}=136.89 \end{array}

\begin{aligned} &\text { Rounding off to nearest integer }\\ &x=137 \end{aligned}

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Deependra Verma

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