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A radiation of 200 W is incident on a surface which is 60% reflecting and 40% absorbing. The total force on the surface is

Option: 1

1.07 \times 10^{-6} \mathrm{~N}


Option: 2

1.3 \times 10^{-6} \mathrm{~N}


Option: 3

1.07 \times 10^{-7} \mathrm{~N}


Option: 4

1.03 \times 10^{-7} \mathrm{~N}


Answers (1)

\mathrm{\begin{aligned} & F_{\text {total }}+F_{\text {ref }}+F_{\text {abs }} \\ & =\frac{1.2 P}{c}+\frac{0.4 P}{c}=\frac{1.6 P}{c} \\ & =\frac{1.6 \times 200}{3 \times 10^8}=1.07 \times 10^{-6} \mathrm{~N} \end{aligned}}

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Ramraj Saini

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