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  • A radio wave of frequency  enters a ferrite rod. If <img alt="\mathrm{\vare

A radio wave of frequency 90 \mathrm{MHz} enters a ferrite rod. If \mathrm{\varepsilon_r=10^3 \, and\, \, \mu_r=10}, then the velocity and wavelength of the wave in ferrite are

Option: 1

3 \times 10^8 \mathrm{~ms}^{-1} ; 3.33 \times 10^{-2} \mathrm{~m}


Option: 2

3 \times 10^6 \mathrm{~ms}^{-1} ; 3.33 \times 10^{-2} \mathrm{~m}


Option: 3

3 \times 10^8 \mathrm{~ms}^{-1} ; 3.33 \times 10^{-1} \mathrm{~m}


Option: 4

3 \times 10^7 \mathrm{~ms}^{-1} ; 3.33 \times 10^{-3} \mathrm{~m}


Answers (1)

\mathrm{\begin{aligned} & v_{\text {ferrite }}=\frac{c}{\sqrt{\mu_r \varepsilon_r}}=\frac{3 \times 10^8}{\sqrt{10 \times 10^{33}}}=3 \times 10^6 \mathrm{~ms}^{-1} \\ & \lambda_{\text {ferrite }}=\frac{v_{\text {ferrite }}}{v}=\frac{3 \times 10^6}{90 \times 10^6}=3.33 \times 10^{-2} \mathrm{~m} \end{aligned} }

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Sumit Saini

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