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A radioactive isotope having a half -life period of 3 days was received after 12 days. If 3g of the isotope is left in the container what would be the initial mass of the isotope?

Option: 1

12g


Option: 2

36g


Option: 3

48g


Option: 4

24g


Answers (1)

best_answer

No. of half-lives, n=12/3 ?=4
Amount left after n half-lives   A = \frac{A_{0}}{2^{n}}?
 

\\3g = \frac{A_{0}}{2^{4}} \\ \\ 3g = \frac{A_{0}}{16} \\ \\ 48g = A_{0}??
 

Posted by

Rakesh

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