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A radioactive nucleus decays by two different process. The half life of the first process is 5 minutes and that of the second process is 30 \mathrm{~s}.The effective half-life of the nucleus is calculated to be \frac{\alpha}{11} \mathrm{~s}. The value of \alpha is ________.  

Option: 1

300


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

 
\frac{\mathrm{dN}}{\mathrm{dt}}=-\left(\lambda_{1}+\lambda_{2}\right) \mathrm{N}
\lambda_{\text {eq }}=\lambda_{1}+\lambda_{2}
\frac{1}{\mathrm{t}_{\frac{1}{2}}}=\frac{1}{300}+\frac{1}{30}=\frac{11}{300}
\mathrm{t}_{1 / 2}=\left(\frac{300}{11}\right) \sec

Ans: 300

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