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  • A random variable X has the following probability distribution: X 0 <td

A random variable X has the following probability distribution:

X 0 1 2 3 4
P(X) k 2k 4k 6k 8k

 

The value of P(1<X<4\mid X\leq 2) is equal to:

Option: 1

\mathrm{\frac{4}{7}}


Option: 2

\mathrm{\frac{2}{3}}


Option: 3

\mathrm{\frac{3}{7}}


Option: 4

\mathrm{\frac{4}{5}}


Answers (1)

best_answer
X 0 1 2 3 4
P(X) k 2k 4k 6k 8k

\begin{aligned} \mathrm {k+2 k+4 k+6 k+8 k} &=\mathrm {1} \\ \mathrm {k=\frac{1}{21}} &=\mathrm {\frac{p(x=2)}{p(x \leq 2)} }\\ \mathrm {P(1<x<4 / x \leq 2)}=& \mathrm {\frac{4 k}{k+2 k+4 k}} \\ &=\mathrm {\frac{4}{7}} \end{aligned}

Posted by

Shailly goel

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